find the sum of first 100 integers divisible by 7
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Answered by
1
Answer:
Step-by-step explanation:
Answered by
1
Answer:
Step-by-step explanation:
A.P = 7, 14, 21,............ 700
n = 100
S14 = n/2 ( 2a + (n-1)d )
= 50 ( 7 + 700 )
= 50 x 707
= 35350
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Input parameters & values:
The number series 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, . . . . , 700.
The first term a = 7
The common difference d = 7
Total number of terms n = 100
step 2 apply the input parameter values in the AP formula
Sum = n/2 x (a + Tn)
= 100/2 x (7 + 700)
= (100 x 707)/ 2
= 70700/2
7 + 14 + 21 + 28 + 35 + 42 + 49 + 56 + 63 + 70 + 77 + . . . . + 700 = 35350