Math, asked by aaisham977, 1 year ago

Find the sum of first 100 natural numbers in arithmetic progression

Answers

Answered by abhinavv829
2

Answer:

let the a.p be 1 2 3 4.....100

a=1

d=1

an=100

an=a+(n-1)d

100=1+(n-1)1

=100

s.n =n/2[ 2a+(n-1)d]

       putting all values we got 5050

Step-by-step explanation:


abhinavv829: i think it is correct if u got this wrong then try ap 1 2 3 4...99 :)
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