Find the sum of first 100 natural numbers in arithmetic progression
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Answer:
let the a.p be 1 2 3 4.....100
a=1
d=1
an=100
an=a+(n-1)d
100=1+(n-1)1
=100
s.n =n/2[ 2a+(n-1)d]
putting all values we got 5050
Step-by-step explanation:
abhinavv829:
i think it is correct if u got this wrong then try ap 1 2 3 4...99 :)
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