find the sum of first 100 positive integer
gunnaraju:
5050
Answers
Answered by
35
consider..
two such 1 to 100 numbers are there in reverse order
1,2,3,4,5,6,......100
100,99,98.......1
add the above n below figures..
so we will get 101 at any point
1+100, 2+99.......100+1
so we have 100 of such 101
so 100×101
but we only need one set of 100
so divided by 2
so, 100×101=10100÷2=5050
two such 1 to 100 numbers are there in reverse order
1,2,3,4,5,6,......100
100,99,98.......1
add the above n below figures..
so we will get 101 at any point
1+100, 2+99.......100+1
so we have 100 of such 101
so 100×101
but we only need one set of 100
so divided by 2
so, 100×101=10100÷2=5050
make it brainliest if u like it, tqqq
It was little complicated though
Check mine
it was said by.. srinivasa ramanujam... just shared so that everybody cud become creative... ya ive seen n i too knew dat
ok
Answered by
50
Answer:
Positive integers=1.2.3.4...........100
n=100
Sum=n/2(2a+(n-1)d)
=100/2(2×1+(100-1)1)
=50(101)
= 5050
I hope it helps and thanks for the question
Thanks for your answer hitesh...it was an easy method....keep it up...✌️
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