Question

Find the sum of first 100 terms of natural numbers

Answer 1

Answer:

ɢɪᴠᴇɴ ǫᴜᴇs ɪs ᴛᴏ ғɪɴᴅ ᴛʜᴇ sᴜᴍ ᴏғ ɴᴀᴛᴜʀᴀʟ ɴᴜᴍʙᴇʀs ғʀᴏᴍ 1+2+___+100

ʟᴇᴛ A ʙᴇ ᴛʜᴇ ғɪʀsᴛ ᴛᴇʀᴍ ᴀɴᴅ ᴅ ʙᴇ ᴀ ᴄᴏᴍᴍᴏɴ ᴅɪғғᴇʀᴇɴᴄᴇ

ғɪʀsᴛ ᴛᴇʀᴍ=ᴀ-1

ᴄᴏᴍᴍᴏɴ ᴅɪғғᴇʀᴇɴᴄᴇ=ᴅ=1

Lᴀsᴛ ᴛᴇʀᴍ I=100

ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ sᴜᴍ ᴏғ ɴ ᴛᴇʀᴍs ᴏғ ᴀɴ ᴀᴘ sɴ=ɴ/2(ᴀ+I)

s100=100/2(1+100)

=50(101)

=5050

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ ʸᵒᵘ...ꨄ︎

Answer 2

Answer:

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To find:-

• The sum of first 100 terms of natural numbers.

Solution:-

The sum of first 100 terms of natural numbers is in A.P.

Let,the given A.P be

Sn=1+2+3+.....................+99+100

here,

a=1

d=t2-t1

=2-1

=1

n=100

We know that,

Formula for finding the sum of an A.P

$\mathsf{ \dfrac{n}{2}}$×{2a+(n-1)d}

Putting the value in the formula,we get

Sn=$\mathsf{ \dfrac{100}{2}}$×{2.1+(100-1)1}

=50×(2+99)

=50×110

=5500

•°•the sum of first 100 terms of natural number is 5500

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$\huge\green{Thanks}$