Question

find the sum of first 100 terms which are divisible by 5

Answer 1

Step-by-step explanation:

sn=5/2+(2(100-1)x5

solve this u get urs answer perfectly

Answer 2

ap=5,10,15,,,,,,,500

a=5

n=100

d=5

sn=?

sn=n/2{2a+(n-1)d}

sn=50{10+(99×5)}

sn=50(505)

sn=27050