Find the sum of first 1000 positive integer.
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Answered by
45
Sum of first 1000 positive integers
positive integers start from 1
so, 1,2=3,4,.........1000
We hve to find the sum, so we use the formula
Sum= n/2(2a+(n-1)d)
here a=1
d=2-1=1
n=1000
putting these values in formula
sum= n/2(2a+(n-1)d)
sum= 1000/2(2×1+ (1000-1)1)
sum= 1000/2(2+999)
sum = 500×1001
sum = 500500....
hope this will help u.
sshreya0:
:)
Answered by
10
Answer:500500
Step-by-step explanation:
Sum of first n positive integers is n(n+1)/2
Here n=1000
So sum= (1000x1001)/2=500500
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