Find the sum of first 1000 positive integers.
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Answer:
let S=1+2+3+.....+1000
using the formula s(n)=n/2(a+1) for the sum of first n terms of an AP,
we have
S1000=1000/2(1000+1)
=500×1001
=500500
so, sum of first 1000 positive integers is 500500
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