Question

Find the sum of first 1000 positive integers

Answer 1

Hello friend !!!

Here's the answer you are looking for

The sum of first n positive integers is n(n+1) / 2

So the sum of first 1000 positive integers is

=1000 (1000+1) / 2

=1000 (1001) / 2

=500 × 1001

= 500500


★★ HOPE THAT HELPS ☺️ ★★

Answer 2

Hi ,

first 1000 positive integers = { 1, 2 , 3 .., 1000}

sum of first n natural numbers = n(n + 1 )/2

Here , n = 1000

S1000 = [ 1000(1000 + 1 ) ] /2

= ( 1000 × 1001 ) / 2

= 500500

I hope this helps you.

:)