find the sum of first 1000 positive intergers
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Answer:
500500
Step-by-step explanation:
Let S = 1 + 2 + 3 + . . . + 1000 Using the formula Sn =n/2(a+1) for the sum of the first n terms of an AP, we have S1000=1000/2(1+1000)=500x1001=500500 So, the sum of the first 1000 positive integers is 500500.
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