Question

Find the sum of first 11 positive numbers which are multiples of 6

Answer 1

Sn = n\2 [ 2a + ( n - 1 )d ]

= 11\2 [ 2*6 + ( 11 - 1 )6 ]  (since 6 is the first positive multiple and on adding 6 the multiples go on )

= 11\2 [ 12 + 60 ]

= 11\2 * 72

= 11 * 36

= 396

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Answer 2

Answer:

here is ur answer

Step-by-step explanation:

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