Find the sum of first 11 term of ap 2,6,10
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2
Answer:
242
Step-by-step explanation:
sum of n terms in A.P=n/2[2a+(n-1)d]
n=11
a=2
d=6-2=4
11/2[2*2+(11-1)4]
11/2[4+40]=11/2[44]=11*22=242
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