Find the sum of first 11t terms of the ap 2,9,16,23....
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Answer:
a=2
d=a2-a1=9-2
d=7
n=11
Sn=n/2(2a+(n-1)d)
S11=11/2(2×2+(11-1)7)
=11/2(4+10×7)
=11/2(4+70)
=11/2(74)
=11×37
S11=407
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