Question

Find the sum of first 12 natural numbers each of which is a multiple of 8

Answer 1

Answer:

$\begin{lgathered}\huge\green {♡}\blue {Answer}\green{♡}\\\end{lgathered}$

BY CALCULATING,THE ANSWER IS 624..

Answer 2

First multiple of 8= (a1)=8

Second multiple of 8=(a2)=16

Last term=l=12×8=96

Total number of terms= n=12

Sn=n/2 (a+l)

S12=12/2 (8+96)

S12=6×104

S12=624