Question

:)
Find the sum of first 125 even natural numbers.​

Answer 1

$\boxed { ANSWER \;is\; 15750}$

SOLUTION

The first 125 even natural numbers are - 2 , 4 , 6 , .............. 250 .

This forms an AP whose ,

First Term of the AP (a) = 2

Common Difference (d) = 2

Last Term (an) = 250

Total Number of Terms (n) = 125

SUM of The AP

Sum of the AP ,

$\sf S(n) = \dfrac{n}{2} (a+an)$

$\sf S(n) = \dfrac{125}{2} (2+250)$

$\sf S(n) = \dfrac{125}{2} * 252$

$\sf S(n) = 125* 126$

∴ Sum of first 125 even natural numbers = 125 × 126 = 15750