find the sum of first 12multiples of2and 3 using the formula
Answers
Answered by
1
Answer:
MULTIPLES OF 2 AND 3
A1 = 6 , A2 = 12 , A3 = 18
SO, D = a2 - a1 ==> 12-6 ==> 6
A = 6
SUM OF 12 TERM ==> n/2 [2a+(n-1)d]
===> 12/2 [2(6) + (12-1)6]
===> 6[12 + 66]
===> 6[78]
==> 468
thanuja7:
haa
and we have a1 = 6
a2 = 12
because they are multiple
what is the value of D
of 2 and 3 both
only
d = a2-a1 = 12-6 ==> 6
so put the value properly you can see answer
upper dekh lo maine kiya hai bro
Similar questions