Find the sum of first 14 terms of the sequence -3, 3, 9, 15.
Answers
Answered by
1
Answer:
Step-by-step explanation:
This is an AP
with a=-3
d=6
Sn = n/2(2a+(n-1)d)
= 14/2(2(-3)+(14-1)6)
7(-6+13*6)
504 ans...
Answered by
4
Answer:
a = -3
d = 3-(-3) = 6
a14 = a + 13d
= -3 + 13(6)
= -3 + 78
= 75
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