find the sum of first 15 multiples of 8
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Answer:
(is 960) answer ❤️ please
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0
Step-by-step explanation:
The multiples of 8 are 8,16,24,32…
These are in an A.P., having first term as 8 and common difference as 8.
Therefore, a=8,d=8, S ^15=?
S^n= 2/n[2a+(n−1)d]
S^15 = 2/15 [2(8)+(15−1)8]
= 2/15 [16+(14)(8)]
= 2/15×128
=960
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