Math, asked by harshitsingh2099, 4 days ago

find the sum of first 15 multiples of 8​

Answers

Answered by Anonymous
2

Answer:

(is 960) answer ❤️ please

Answered by dekatekanak
0

Step-by-step explanation:

The multiples of 8 are 8,16,24,32…

These are in an A.P., having first term as 8 and common difference as 8.

Therefore, a=8,d=8, S ^15=?

S^n= 2/n[2a+(n−1)d]

S^15 = 2/15 [2(8)+(15−1)8]

= 2/15 [16+(14)(8)]

= 2/15×128

=960

Similar questions