Question

find the sum of first 15 multiples of 8

Answer 1

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HERE IS UR ANSWER ⬇️⬇️
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a = 8
n = 15
d = 8

So,Sn = n/2 [2a +(n-1)d)
= 15/2 (2×8 + (14)8]
= 15/2 [16 +112]
= 15/2 [128]
= 15 [64]
= 960

So,Sum of first 15 multiples of 8 is 960✔✔
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Answer 2

Answer:

THE NUMBERS MULTIPLES OF 8 ARE 8,16,24,32........…….

THESE NUMBER FORM AN AP WITH COMMON DIFFERENCE 8 AND THE FIRST TERM 8

A=8,

D=8,

S15=?

SN=N/2[2A+(N-1)D)

S15=960

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