find the sum of first 15 multiples of 8
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hey mate ,,,
here's ur answer.....
The first 15 multiples of 8 are 8 × 1, 8 × 2, 8 × 3, ... 8 × 15 i.e., 8, 16, 24 ,32 ,40............ 120, which is an AP and here a=8 d= 8 Therefore sum of 1st 15 multiples of sum=n/2 (a+l) sum= 15/2(8+120) =15/2 ×128 = 15 × 64 = 960..
hope it is helpful .....
here's ur answer.....
The first 15 multiples of 8 are 8 × 1, 8 × 2, 8 × 3, ... 8 × 15 i.e., 8, 16, 24 ,32 ,40............ 120, which is an AP and here a=8 d= 8 Therefore sum of 1st 15 multiples of sum=n/2 (a+l) sum= 15/2(8+120) =15/2 ×128 = 15 × 64 = 960..
hope it is helpful .....
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