find the sum of first 15 multiplesof 8 .
Answers
Answered by
1
Answer:
VIDEO EXPLANATION

ANSWER
The multiples of 8 are 8,16,24,32…
These are in an A.P., having first term as 8 and common difference as 8.
Therefore, a=8,d=8, S15=?
Sn=2n[2a+(n−1)d]
S15=215[2(8)+(15−1)8]
=215[16+(14)(8)]
=215×128
=960 Answer....
Similar questions