find the sum of first 15terms having nth term as
an=3+4n
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nth term = 3 + 4n
.°. 15th term = 3 + 4×15 = 63
=> a15 = a + (15-1)d
=> 63 = 3 + 14d
=> 60 = 14d
=> d = 60/14= 30/7
.°. S15 = 15/2 [2×3 + 14×30/7]
S15 = 15(3 + 30) = 15×33 = 495
Ans : 495
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.°. 15th term = 3 + 4×15 = 63
=> a15 = a + (15-1)d
=> 63 = 3 + 14d
=> 60 = 14d
=> d = 60/14= 30/7
.°. S15 = 15/2 [2×3 + 14×30/7]
S15 = 15(3 + 30) = 15×33 = 495
Ans : 495
Hote it helps
If it does, plz mark as brainliest
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