Find the sum of first 16 multiples of 3
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Answer:
408
Step-by-step explanation:
There are two steps:
1.) 3+6+9+12+15+18+21+24+27+30+33+36+39+42+45+48 = 408
2.) Sn = n/2 {2a + (n-1) × d}
S16 = 16/2 {2×3 + (16-1) × 3}
S16 = 8 (6+45)
S16 = 8 × 51
S16 = 408
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Hope this helps........
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