find the sum of first 16 terms of an ap 2,6,10..
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Sum of n terms is n/2(2a+(n-1)d)
here we have a= 2, d=4 and n=16
substituting the values we get
S(16) = 16/2(2x2+(15)4)
= 8(4+60)
= 8(64)
= 512
Hence sum of 16 terms is 512.
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