Find the sum of first 16 terms of the A.P. 1,1.5, 2,2.5. .....
Answers
Answered by
6
Step-by-step explanation:
a = 1,
d = a2-a1 = 1.5 - 1 = 0.5
Sn = n ( 2a + (n-1)d)
2
=16(2×1 + (16 - 1)×0.5)
2
= 8(2 + 17.5)
= 8(19.5)
=156
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Answered by
0
Answer:
76
Step-by-step explanation:
a=1
d=0.5
n=16
Sn=n/2(2a+(n-1)d)
=16/2(2+(16-1)0.5)
=8(2+(15)0.5)
=8(2+7.5)
=8(9.5)
=76
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