Question

Find The sum of first 16 terms of the AP: 10, 6, 2,...​

Answer 1

Answer:

The answer is -320.

Step-by-step explanation:

a=10, n=16, d=6−10=−4

We know that

Sn=n/2[2a+(n−1)d]

∴S16=16/2[2×10+(16−1)(−4)]

⇒S16=8[20+15(−4)]

⇒S16=8×(−40)

⇒S16=−320

Hope it helps...