Question

find the sum of first 16th term of the ap 10 6 2..........​

Answer 1

$\huge\red{Answer}$

ᴀ = 10

ᴅ = 6-10

= -4

ꜱ16 = ɴ/2 (2ᴀ+(ɴ-1)ᴅ)

= 16/2×(2×10+(16-1)×(-4))

= 8×(20-60)

= 8×(-40)

= -320

ʜᴏᴩᴇ ɪᴛ ʜᴇʟᴩꜱ yᴏᴜ !!!

Answer 2

ANSWER":==

AP is n/2(2a+(n-1)d)

here n=16 a=10 d=6-10=2-6=-4

so sum of first 16 terms

=16/2(2·10+(16-1)·-4)

=8(20+15·-4)

=8(20-60)

=8(-40)

=-320

.:. the answer is -320

hope it helps