Find the sum Of First 20 positive Intergers Divisible by3
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a= 3 d = 3 n = 20
Sn = n/2 [ 2a + (n-1)d ]
=> Sn = 20/2 [ 2*3 + (20-1)*3 ]
=> 10[6 + 57]
=> 10[63]
=> 630 answer
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