Find the sum of first 20 teams the sequence 4,7,10..
Answers
Answered by
2
Answer:
650
Step-by-step explanation:
sum of n terms = n/2(2a +{n-1}d)
n=20, a=4, d=3,
.'.replacing the values in the formula
=20/2(2*4+{20-1}3)
=10(8+57)
=10*65
=650
Answered by
0
Answer:
650
Step-by-step explanation:
This seems to be an AP with a common difference of 3 terms
sum of AP = (First term+ Last term)* number of terms/2
Last term= first term + (number of terms-1)* common difference
4+(20-1)3
= 61
Sum of 20 terms = (4+61)*20/2
=650
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