find the sum of first 20 term of AP 13,8,3.......
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Answered by
7
a=13, d=5, t20=??
t20=a+(n-1)d
t20=13+(20-1)×5
=13+19×5
=13+95
=108
the 20 term is 108
t20=a+(n-1)d
t20=13+(20-1)×5
=13+19×5
=13+95
=108
the 20 term is 108
Answered by
6
13,8,3,......
a=13;d= 8-13=-5
here 20 term there fore n=20
sum of 20 term = n/2[2a+(n-1)d]
=20/2[2(13)+(20-1)(-5)]
=10[26+(19)(-5)]
=10[26-95]
=10(-66)
=-660
a=13;d= 8-13=-5
here 20 term there fore n=20
sum of 20 term = n/2[2a+(n-1)d]
=20/2[2(13)+(20-1)(-5)]
=10[26+(19)(-5)]
=10[26-95]
=10(-66)
=-660
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