Find the sum of first 20 terms of an AP, whose nth term is 9m-1
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6
Answer:
1550
Step-by-step explanation:
the the first term of the AP
a1= 9(1)-1= 8
the 28th term of AP
a2= 9(20)-1= 179
the common difference d of the AP is
a1-a2=[9(2)-1]- 8= 9
sum of the first 20 terms of the AP
s20= 20/2(-2(8)+(20-1)9) = 1550
hope it helps.
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