Question

find the sum of first 200 natural numbers

Answer 1

a = 1

d = 1

n = 200

Sn = n/2[ 2a +(n-1) d]

Required sum = 200/2 [ 2 × 1 + (200 - 1)(1)]

= 100 ( 2 + 199)

= 100 × 201

= 20100

Answer 2

Answer:

Sum of first 200 natural numbers= 20100

Explanation:

We know that,

$\boxed { Sum \: of \: first\: n\: natural \: numbers\\ = \frac{n(n+1)}{2}}$

Now ,

Here, n = 200

Sum of first 200 natural numbers = $\frac{200(200+1)}{2}$

= [tex]100\times 201[\tex]

= $20100$

Therefore,

Sum of first 200 natural numbers = 20100

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