find the sum of first 200 positive odd integers
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S=1+3+5+7+9+…………………..+200 terms.
This is an A.P. in which a=1 , d =2 , n=200 , S200=?
Sn=n/2.[2a+(n-1).d]
S200=200/2[2.1+(200–1).2]
S200 =100×(2+398) = 100×400= 40000 Answer.
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1
Answer:
40000
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