Question

find the sum of first 200 positive odd integers​

Answer 1

S=1+3+5+7+9+…………………..+200 terms.

This is an A.P. in which a=1 , d =2 , n=200 , S200=?

Sn=n/2.[2a+(n-1).d]

S200=200/2[2.1+(200–1).2]

S200 =100×(2+398) = 100×400= 40000 Answer.

Answer 2

Answer:

40000

Step-by-step explanation:

Please find the attached image.