find the sum of first 21 terms if middle term of an AP is 20
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Answered by
2
S21=?
a11=20
a11=a+10d
so, 20=a+10d
s21=21/2(2a+20d)
=21a+210d
=21(a+10d). (a+10d=20)
=21* 20
=420
a11=20
a11=a+10d
so, 20=a+10d
s21=21/2(2a+20d)
=21a+210d
=21(a+10d). (a+10d=20)
=21* 20
=420
Joshuawoskk:
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Answered by
2
Middle term = 11 = 20
So, a11 = a + 10d
20 = a+10d --------------------------- (1)
We know sum of n terms = n/2(a+(n-1)d)
Sum of first 21 terms = 21/2(2a+20d)
= 21a + 210d
= 21(a+10d) --------- from (1)
= 21 * 20
= 420.
Hope this helps!
So, a11 = a + 10d
20 = a+10d --------------------------- (1)
We know sum of n terms = n/2(a+(n-1)d)
Sum of first 21 terms = 21/2(2a+20d)
= 21a + 210d
= 21(a+10d) --------- from (1)
= 21 * 20
= 420.
Hope this helps!
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