find the sum of first 22 terms of an Ap in
which a=7 and 22nd
term is 149.
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Answer:
a = 7
an = 149
d= ?
n = 22
S22 = ?
the value of d is
a+ ( n-1)d = an
7+(22-1) d = 149
7+21d = 149
21d = 149-7
d = 142 /21
d = 7
the shm of 22 th term is
Sn = n/2 + [2a + ( n-1) d]
22/2 + [ 2×7 + (22-1) 7]
= 11 + 14 + 147
= 172
the sum of 22 term is 172 .
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