Find the sum of first 22 terms of an AP in which d = 7 and 22nd term is 149.
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Answered by
1
Answer:
Given that
d = 7
22nd term = 149
a + 21 × d = 149
a + 21 × 7 = 149
a + 147 = 149
a = 149 - 147
a = 2
Now ,
Sum of first 22 terms
S^n = (n/2) [ 2a + ( n - 1 ) d ]
===> 22/2 [ 2 × 2 + ( 22 - 1 ) 7 ]
===> 11 [ 4 + 21 × 7 ]
===> 11 [ 4 + 147 ]
===> 11 ( 151 )
S^22 ===> 1661
The sum of first 22 terms is 1661
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