Find the sum of first 22 terms of an AP in which d = 7 and 22nd term is 149.
Answers
Answered by
1
Step-by-step explanation:
formula: n/2(2a+(n-1)d)
or n/2(first term +last term)
here last is 149
first=149-7×22=-6
so sum is 11×(-6+149)
=143×11
=1573
this is the basic idea to solve fastly.
Answered by
2
Answer: 1661
Step-by-step explanation:
Given
d = 7
22nd term = 149
a+21d = 149
a + 21(7) = 149
a + 147 = 149
a = 2
using formula: Sn = (n/2) [2a + (n - 1) d]
S₂₂ = (22/2) [ 2 × 2 + (22 - 1)7 ]
S₂₂ = 11 [4 + 21(7)]
S₂₂ = 11 [4 + 147]
S₂₂ = 11 × 151
S₂₂ = 1661
Thus, the sum of first 22 terms is 1661.
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