Math, asked by mazra1064, 4 months ago

find the sum of first 22 terms of an AP /in which d=7 and 22nd term is 149






Answers

Answered by telltosiddharth
0

Answer:

guu galnai ga guu

Step-by-step explanation:

Answered by Anonymous
0

Step-by-step explanation:

AnswEr :

\frak{Given}\begin{cases} \sf{\: Common \: difference \: (d) = 7}\\\sf{ \: 22nd \ term = 149} \end{cases}

We've to find out the sum of 22 terms. So, n = 22

By using nth term Formula of the AP :

\star \ \boxed{\sf{\purple{a_{n} = a + (n -1)d}}}

\underline{\bf{\dag} \:\mathfrak{Substituting \ Values \  in \ the \ formula \ :}}

:\implies\sf 149 = a + (22 - 1) \times 7 \\\\\\:\implies\sf  149 = a + 21 \times 7 \\\\\\:\implies\sf   149 = a + 147\\\\\\:\implies\sf  a = 149 - 147\\\\\\:\implies\boxed{\frak{\purple{a = 2}}}

\therefore\underline{\textsf{ Here, we get value of the First term (a) of AP \textbf{2}}}. \\

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For any Arithmetic Progression ( AP ), the sum of n terms is Given by :

\bf{\dag}\quad\large\boxed{\sf S_n = \dfrac{n}{2}\bigg(a + l\bigg)}

Where :

n = no. of terms

a = First Term

l = Last Term

:\implies\sf S_{22} = \dfrac{\cancel{22}}{\cancel{\:2}} \bigg(2 + 149 \bigg) \\\\\\:\implies\sf  S_{22} =  11 \times 151 \\\\\\:\implies\boxed{\frak{\purple{  S_{22} = 1661}}}

\therefore\underline{\textsf{ Hence, Sum of 22 terms of the AP is \textbf{1661}}}. \\

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\qquad\qquad{\underline{\underline{\dag \: \bf\:Formulaes \ of \: the  \:AP\: :}}}\\ \\⠀⠀

To find out the nth term of the AP \sf\pink{a_n + (n - 1)d}⠀⠀⠀

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To find out the Sum of the AP = \sf\purple{S_n = \dfrac{n}{2} \bigg[\sf 2a + (n - 1)d \bigg]}

To find out the sum of all terms have the last term of the AP 'l' = \sf \blue{\dfrac{n}{2}(a + l)}.

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