Find the sum of first 22 terms of an AP in which d=7 and 22nd term in 149
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Answered by
0
Answer:
The sum of first 22 terms is 1661
Step-by-step explanation:
Given 22nd term is 149
Then,
a+21d=149
a+21(7)=149
a=149-147
a=2
Sum of 22 terms is =n/2(2a+(n-1)d)
=22/2(2(2)+21(7))
=11(4+147)
=11(151)
=1661
The answer is 1661
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Answered by
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149=a+(22-1)7
149=a+21×7
149=a+147
149-147=a
a=2
S22=n/2[2a+(n-1)d]
S22=22/2[2×2+(22-1)7]
S22=11[4+147]
S22=11×151
S22=1661
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