Question

find the sum of first 22 terms of an ap in which day is equal to 7 and 22​

Answer 1

Answer:

1661

Step-by-step explanation:

Ap=a+(n-1)d

149=a+(22-1)7

149=a+21x7

149-147=a

2=a

Sn=n/2(a+l)

Sn=22/2(2+149)

Sn=11x151

Sn=1661

HOPE THIS HELPS U

Answer 2

Hi dear

Given d = 7,

22nd term = 149 , 

⇒ a+21d = 149

⇒a+21(7) = 149

⇒a+147 = 149

⇒a=149-147=2

Sn = (n/2)(2a+(n-1)d)

S₂₂ = (22/2)(2×2+(22-1)7)

S₂₂ = 11(4+21(7))

S₂₂ = 11(4+147)

S₂₂ = 11(151)

S₂₂ = 1661.

Brainiest answer please.