Question

Find the sum of first 22 terms of an appointment in which d=7and 22nd term is 149

Answer 1

Answer:

HELLO ,

a+21d=149

a+21(7)=149

a= 149-147

a=2

sn = n/2 (2a + (n-1)d)

s22 = 22/2 ( 4+21(7))

s22 = 11( 151)

s22 = 1661

good luck

Answer 2

Answer:

a + 21d = 149

a + 21*7 = 149

a = 149 - 147 = 2

S22 = 22/2 ( 2*2 + {22-1} * 7 )

= 11 ( 4+147)

=11(151)

=1661

Step-by-step explanation: