Find the sum of first 22 terms of an appointment in which d=7and 22nd term is 149
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Answered by
1
Answer:
HELLO ,
a+21d=149
a+21(7)=149
a= 149-147
a=2
sn = n/2 (2a + (n-1)d)
s22 = 22/2 ( 4+21(7))
s22 = 11( 151)
s22 = 1661
good luck
Answered by
1
Answer:
a + 21d = 149
a + 21*7 = 149
a = 149 - 147 = 2
S22 = 22/2 ( 2*2 + {22-1} * 7 )
= 11 ( 4+147)
=11(151)
=1661
Step-by-step explanation:
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