Question

find the sum of first 22 terms of the sequence 6,10,14..?​

Answer 1

Answer:

a22=90

Step-by-step explanation:

we know arithmetic sequence formula for n term is:

$a_{n}=a_{1}+(n-1)d$

a1 = 6 = the first term in the sequence

d = 4 = the common difference between terms

Replace n=22 for 22 terms of sequance we get

a22=6+(22-1)4

$a22=6+(22-1)4\\a22=90$