Question

find the sum of first 223 even natural number​

Answer 1

$\large \underline{ \underline{\bold{ \: Answer : \: \: \: }}}$

$\to$ 12432

$\large \underline{ \underline{\bold{ \: Explanation : \: \: \: }}}$

Given ,

First term ( a ) = 2

Last term ( l ) = 222

Common difference ( d ) = 2

$\huge{ \star}$ nth term = a + ( n - 1)d

$\to$ 222 = 2 + ( n - 1)2

$\to$ 220 = 2n - 2

$\to$ 2n = 222

$\to$ n = 222 / 2

$\to$ n = 111

$\huge{ \star}$ Sum of nth term = n/2 ( a + l)

$\to$ Sum = 111/2 ( 2 + 222 )

$\to$ Sum = 111/2 ( 224 )

$\to$ Sum = 111 × 112

$\to$ Sum = 12432

Hence , the required number is 12432