Question

Find the sum of first 24 terms of an AP, where AP is 5, 8, 13....​

Answer 1

Step-by-step explanation:

hope this helps uh...........Mate

Answer 2

Answer:

There is a mistake in question it should be 11 in place of 13, after that only d is constant, otherwise this in not a ap

948

Step-by-step explanation:

Given:

a = 5

n = 24

d = a₂ - a₁ = 8 - 5 = 3

Now,

Sn = n/2 {2a + (n-1)d}

    = 24/2 {2 × 5 + ( 24 - 1 )3}

   = 12 {10 + 23 × 3}

   = 12 {10 + 69}

   = 12 × 79

   =   948