Question

Find the sum of first 24 terms of an AP, whose general term is 3+2/3 n.​

Answer 1

hey buddy

so here general term=3+2/3n

1st term=3+2/3(1)

=11/3

2nd term=3+2/3(2)

=13/3

3rd term=3+2/3(3)

=5

then here common difference(d)=2/3

1st term(a)=11/3

then sum of 1st 24 terms=n/2[2a+(n-1)d]

=24/2[22/3+23(2/3)]

=12[68/3]

=68*4

=272

HOPE THIS HELPS BUDDY