Question

Find the sum of first 24 terms of the AP 5. 8. 11. 14........​

Answer 1

Step-by-step explanation:

sn= (2a+n-1)d

= (2 ×5+23)3

=( 10+23) 3

(33)3

99

Answer 2

Step-by-step explanation:

given that :

first term a = 5

common difference d = 8 - 5 = 3

nth terms = 24

Then according to questions:

$sn = \frac{n}{2} (2a + (n - 1)d) \\ \\ = \frac{24}{2} (2 \times 5 + (24 - 1)3) \\ \\ = 12(10 + 23 \times 3) \\ \\ = 12(10 + 69) \\ \\ = 12 \times 79 \\ \\ = 948$