FIND THE SUM OF FIRST 24 TERMS OF THE LIST OF NUMBERS WHOOSE nTH TERM IS An = 3 +2n
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24x
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As an = 3 + 2n, so, a1 = 3 + 2 = 5 a2 = 3 + 2 × 2 = 7 a3 = 3 + 2 × 3 = 9 List of numbers becomes 5, 7, 9, 11, . . . Here, 7 – 5 = 9 – 7 = 11 – 9 = 2 and so on. So, it forms an AP with common difference d = 2. To find S24, we have n = 24, a = 5, d = 2. Therefore So, sum of first 24 terms of the list of numbers is 672
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