Find the sum of first 24 terms of the list of numbers whose nth term is
given by
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the nth trem is an =3+2n so by using this we can find the value of terms like a1=5'a 2=7a 3=9 and a 24=51 now the first term is 5 and the last term is 5i and the difference is 2 by using the formula for some of u terms i.e an=n / 2 a +( n_1)d) so s 24 = 24/2(10+23.2)i.e 672
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