Question

find the sum of first 24 terms of the list of numbers whose nth term is given by an = 3+2n

Answer 1

First term = 3+2*1
= 5
24th term = 3+2*24
= 51
Sum =
$\frac{n}{2} (a + l)$
$= \frac{24}{2} (5 + 51) \\ = 12(56) \\ = 672$

Answer 2

Hope this helps, mark brainliest if it did :)