find the sum of first 24 terms of the list oif number whose n th term is give by an =3+2n
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an = 3+2n
So, a1 = 3 + 2*1 = 5
and, a2 = 3 + 2*2 = 7
So, d = a2- a1 = 2
and, a = 5
So, S24 = 12[2a+23d] 12[2*5 + 23*2] = 12[10+46]
S24 = 12*56 = 672
So, a1 = 3 + 2*1 = 5
and, a2 = 3 + 2*2 = 7
So, d = a2- a1 = 2
and, a = 5
So, S24 = 12[2a+23d] 12[2*5 + 23*2] = 12[10+46]
S24 = 12*56 = 672
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