Question

find the sum of first 24tetms of the list of numbers whose Nth term is given by An=3+2n​

Answer 1

A1=3+2(1)=5

A2=3+2(2)=7

d=A2-A1=7-5=2

S24=24/2[2(5)+23(2)] =12[10+46]

=12(56)=672